Minimum number of diagonal transversals in a semicyclic diagonal Latin squares of order n, https://oeis.org/A366332 n=1, a(1)=0 Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023 Way of finding: Brute Force + DLX 0 n=3, a(3)=0 - n=5, a(5)=5 Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023 Way of finding: Brute Force + DLX 0 1 2 3 4 2 3 4 0 1 4 0 1 2 3 1 2 3 4 0 3 4 0 1 2 n=7, a(7)=27 Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023 Way of finding: Brute Force + DLX 0 1 2 3 4 5 6 2 3 4 5 6 0 1 4 5 6 0 1 2 3 6 0 1 2 3 4 5 1 2 3 4 5 6 0 3 4 5 6 0 1 2 5 6 0 1 2 3 4 n=9, a(9)=0 - n=11, a(11)=4523 Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023 Way of finding: Brute Force + DLX 0 1 2 3 4 5 6 7 8 9 10 2 3 4 5 6 7 8 9 10 0 1 4 5 6 7 8 9 10 0 1 2 3 6 7 8 9 10 0 1 2 3 4 5 8 9 10 0 1 2 3 4 5 6 7 10 0 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 10 0 3 4 5 6 7 8 9 10 0 1 2 5 6 7 8 9 10 0 1 2 3 4 7 8 9 10 0 1 2 3 4 5 6 9 10 0 1 2 3 4 5 6 7 8 n=13, a(13)=127339 Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023 Way of finding: Brute Force + DLX 0 1 2 3 4 5 6 7 8 9 10 11 12 3 4 5 6 7 8 9 10 11 12 0 1 2 8 9 10 11 12 0 1 2 3 4 5 6 7 4 5 6 7 8 9 10 11 12 0 1 2 3 12 0 1 2 3 4 5 6 7 8 9 10 11 9 10 11 12 0 1 2 3 4 5 6 7 8 5 6 7 8 9 10 11 12 0 1 2 3 4 1 2 3 4 5 6 7 8 9 10 11 12 0 11 12 0 1 2 3 4 5 6 7 8 9 10 6 7 8 9 10 11 12 0 1 2 3 4 5 2 3 4 5 6 7 8 9 10 11 12 0 1 7 8 9 10 11 12 0 1 2 3 4 5 6 10 11 12 0 1 2 3 4 5 6 7 8 9 n=15, a(15)=0 - n=17, a(17)=204330233 Announcement: https://vk.com/wall162891802_2450, Eduard I. Vatutin, Jul 21 2023 Way of finding: Brute Force + DLX 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 2 3 4 5 1 6 7 8 9 10 11 13 14 15 16 12 0 6 9 7 10 8 11 13 15 12 14 16 0 1 2 3 4 5 7 10 8 11 9 13 15 12 14 16 0 2 3 4 5 1 6 13 14 15 16 12 0 2 4 1 3 5 6 9 7 10 8 11 15 16 12 0 14 2 4 1 3 5 6 7 10 8 11 9 13 4 5 1 6 3 7 8 9 10 11 13 15 16 12 0 14 2 8 11 9 13 10 15 12 14 16 0 2 4 5 1 6 3 7 12 0 14 2 16 4 1 3 5 6 7 8 11 9 13 10 15 1 6 3 7 5 8 9 10 11 13 15 12 0 14 2 16 4 9 13 10 15 11 12 14 16 0 2 4 1 6 3 7 5 8 14 2 16 4 0 1 3 5 6 7 8 9 13 10 15 11 12 16 4 0 1 2 3 5 6 7 8 9 10 15 11 12 13 14 3 7 5 8 6 9 10 11 13 15 12 14 2 16 4 0 1 5 8 6 9 7 10 11 13 15 12 14 16 4 0 1 2 3 10 15 11 12 13 14 16 0 2 4 1 3 7 5 8 6 9 11 12 13 14 15 16 0 2 4 1 3 5 8 6 9 7 10 n=19, a(19)=11232045257 Announcement: https://vk.com/wall162891802_2453, Eduard I. Vatutin, Jul 25 2023 Way of finding: Brute Force + DLX 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 2 3 4 5 1 6 7 8 9 10 11 12 13 15 16 17 18 14 0 13 14 15 16 17 18 0 2 4 1 3 5 6 7 10 8 11 9 12 15 16 17 18 14 0 2 4 1 3 5 6 7 8 11 9 12 10 13 7 10 8 11 9 12 13 15 17 14 16 18 0 2 3 4 5 1 6 8 11 9 12 10 13 15 17 14 16 18 0 2 4 5 1 6 3 7 4 5 1 6 3 7 8 9 10 11 12 13 15 17 18 14 0 16 2 17 18 14 0 16 2 4 1 3 5 6 7 8 9 12 10 13 11 15 9 12 10 13 11 15 17 14 16 18 0 2 4 1 6 3 7 5 8 1 6 3 7 5 8 9 10 11 12 13 15 17 14 0 16 2 18 4 14 0 16 2 18 4 1 3 5 6 7 8 9 10 13 11 15 12 17 10 13 11 15 12 17 14 16 18 0 2 4 1 3 7 5 8 6 9 3 7 5 8 6 9 10 11 12 13 15 17 14 16 2 18 4 0 1 16 2 18 4 0 1 3 5 6 7 8 9 10 11 15 12 17 13 14 18 4 0 1 2 3 5 6 7 8 9 10 11 12 17 13 14 15 16 11 15 12 17 13 14 16 18 0 2 4 1 3 5 8 6 9 7 10 12 17 13 14 15 16 18 0 2 4 1 3 5 6 9 7 10 8 11 5 8 6 9 7 10 11 12 13 15 17 14 16 18 4 0 1 2 3 6 9 7 10 8 11 12 13 15 17 14 16 18 0 1 2 3 4 5 n=21, a(21)=0 - Jul 25 2023