Maximum number of diagonal transversals in a diagonalized cyclic diagonal Latin squares of order n, https://oeis.org/Axxxxxx

n=1, a(1)=0
Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023
Way of finding: Brute Force + DLX
0

n=3, a(3)=0
-

n=5, a(5)=5
Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023
Way of finding: Brute Force + DLX
0 1 2 3 4 
2 3 4 0 1 
4 0 1 2 3 
1 2 3 4 0 
3 4 0 1 2 

n=7, a(7)=27
Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023
Way of finding: Brute Force + DLX
0 1 2 3 4 5 6 
2 3 1 5 6 4 0 
5 6 4 0 1 2 3 
4 0 6 2 3 1 5 
6 2 0 1 5 3 4 
1 5 3 4 0 6 2 
3 4 5 6 2 0 1 

n=9, a(9)=269
Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023
Way of finding: Brute Force + DLX
0 1 2 3 4 5 6 7 8 
1 2 3 6 5 7 8 0 4 
6 8 4 5 1 2 7 3 0 
8 4 5 7 2 3 0 6 1 
5 7 0 1 6 8 2 4 3 
3 6 8 4 0 1 5 2 7 
7 0 1 2 8 4 3 5 6 
4 5 7 0 3 6 1 8 2 
2 3 6 8 7 0 4 1 5 

n=11, a(11)=4828
Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023
Way of finding: Brute Force + DLX
0 1 2 3 4 5 6 7 8 9 10 
1 2 3 5 6 9 7 10 0 4 8 
7 10 8 0 3 1 5 9 6 2 4 
3 5 9 4 10 6 8 0 2 7 1 
4 6 7 10 1 8 2 3 9 0 5 
5 9 4 6 8 7 0 1 3 10 2 
10 8 0 1 5 2 9 4 7 3 6 
6 7 10 8 2 0 3 5 4 1 9 
8 0 1 2 9 3 4 6 10 5 7 
2 3 5 9 7 4 10 8 1 6 0 
9 4 6 7 0 10 1 2 5 8 3 

n=13, a(13)=131106
Announcement: https://vk.com/wall162891802_2441, Eduard I. Vatutin, Jul 18 2023
Way of finding: Brute Force + DLX
0 1 2 3 4 5 6 7 8 9 10 11 12 
2 3 1 4 5 6 7 8 9 11 12 10 0 
7 9 8 11 10 12 0 2 1 3 5 4 6 
8 11 9 10 12 0 2 1 3 4 6 5 7 
1 4 3 5 6 7 8 9 11 10 0 12 2 
9 10 11 12 0 2 1 3 4 5 7 6 8 
3 5 4 6 7 8 9 11 10 12 2 0 1 
11 12 10 0 2 1 3 4 5 6 8 7 9 
4 6 5 7 8 9 11 10 12 0 1 2 3 
10 0 12 2 1 3 4 5 6 7 9 8 11 
12 2 0 1 3 4 5 6 7 8 11 9 10 
5 7 6 8 9 11 10 12 0 2 3 1 4 
6 8 7 9 11 10 12 0 2 1 4 3 5 

Jul 18 2023