Minimum number of diagonal transversals in a diagonalized cyclic diagonal Latin squares of order n, https://oeis.org/Axxxxxx

n=1, a(1)=0
Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023
Way of finding: Brute Force + DLX
0

n=3, a(3)=0
-

n=5, a(5)=5
Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023
Way of finding: Brute Force + DLX
0 1 2 3 4 
2 3 4 0 1 
4 0 1 2 3 
1 2 3 4 0 
3 4 0 1 2 

n=7, a(7)=27
Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023
Way of finding: Brute Force + DLX
0 1 2 3 4 5 6 
2 3 1 5 6 4 0 
5 6 4 0 1 2 3 
4 0 6 2 3 1 5 
6 2 0 1 5 3 4 
1 5 3 4 0 6 2 
3 4 5 6 2 0 1 

n=9, a(9)=241
Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023
Way of finding: Brute Force + DLX
0 1 2 3 4 5 6 7 8 
1 2 3 4 6 7 8 0 5 
3 4 6 8 5 1 7 2 0 
6 8 5 7 0 3 1 4 2 
8 5 7 0 1 4 2 6 3 
7 0 1 2 3 8 4 5 6 
2 3 4 6 8 0 5 1 7 
4 6 8 5 7 2 0 3 1 
5 7 0 1 2 6 3 8 4 

n=11, a(11)=4523
Announcement: https://vk.com/wall162891802_2443, Eduard I. Vatutin, Jul 11 2023
Way of finding: Brute Force + DLX
0 1 2 3 4 5 6 7 8 9 10 
2 3 1 4 5 6 7 9 10 8 0 
6 9 7 8 10 0 2 1 4 3 5 
7 8 9 10 0 2 1 3 5 4 6 
1 4 3 5 6 7 9 8 0 10 2 
9 10 8 0 2 1 3 4 6 5 7 
3 5 4 6 7 9 8 10 2 0 1 
8 0 10 2 1 3 4 5 7 6 9 
10 2 0 1 3 4 5 6 9 7 8 
4 6 5 7 9 8 10 0 1 2 3 
5 7 6 9 8 10 0 2 3 1 4 

n=13, a(13)=127339
Announcement: https://vk.com/wall162891802_2441, Eduard I. Vatutin, Jul 18 2023
Way of finding: Brute Force + DLX
0 1 2 3 4 5 6 7 8 9 10 11 12 
2 3 1 4 6 0 8 5 9 11 12 10 7 
6 9 8 11 10 4 12 3 7 5 2 0 1 
10 7 12 5 0 11 2 9 1 3 6 4 8 
8 11 9 10 12 6 7 4 5 0 1 2 3 
12 5 7 0 2 10 1 11 3 4 8 6 9 
1 4 3 6 8 2 9 0 11 10 7 12 5 
9 10 11 12 7 8 5 6 0 2 3 1 4 
7 0 5 2 1 12 3 10 4 6 9 8 11 
11 12 10 7 5 9 0 8 2 1 4 3 6 
5 2 0 1 3 7 4 12 6 8 11 9 10 
3 6 4 8 9 1 11 2 10 12 5 7 0 
4 8 6 9 11 3 10 1 12 7 0 5 2 

Jul 18 2023